• UnderpantsWeevil@lemmy.world
    link
    fedilink
    English
    arrow-up
    19
    ·
    5 months ago

    There’s a Real Analysis proof for it and everything.

    Basically boils down to

    • If 0.(9) != 1 then there must be some value between 0.(9) and 1.
    • We know such a number cannot exist, because for any given discrete value (say 0.999…9) there is a number (0.999…99) that is between that discrete value and 0.(9)
    • Therefore, no value exists between 0.(9) and 1.
    • So 0.(9) = 1
    • Kairos@lemmy.today
      link
      fedilink
      English
      arrow-up
      7
      ·
      5 months ago

      Even simpler: 1 = 3 * 1/3

      1/3 =0.333333…

      1/3 + 1/3 + 1/3 = 0.99999999… = 1

      • UnderpantsWeevil@lemmy.world
        link
        fedilink
        English
        arrow-up
        4
        arrow-down
        1
        ·
        5 months ago

        Even simpler

        0.99999999… = 1

        But you’re just restating the premise here. You haven’t proven the two are equal.

        1/3 =0.333333…

        This step

        1/3 + 1/3 + 1/3 = 0.99999999…

        And this step

        Aren’t well-defined. You’re relying on division short-hand rather than a real proof.

    • Swedneck@discuss.tchncs.de
      link
      fedilink
      English
      arrow-up
      3
      ·
      5 months ago

      the explanation (not proof tbf) that actually satisfies my brain is that we’re dealing with infinite repeating digits here, which is what allows something that on the surface doesn’t make sense to actually be true.

      • UnderpantsWeevil@lemmy.world
        link
        fedilink
        English
        arrow-up
        2
        ·
        5 months ago

        Infinite repeating digits produce what is understood as a Limit. And Limits are fundamental to proof-based mathematics, when your goal is to demonstrate an infinite sum or series has a finite total.